Wie gross darf b\color{red} bb höchstens sein, damit gilt ∫−6b(x+2)3 dx≤0 \displaystyle \int_{-6}^{\color{red}b} (x+ 2)^3 \; dx \leq 0 ∫−6b(x+2)3dx≤0?
b\color{red} bb
∫−6b(x+2)3 dx≤0 \displaystyle \int_{-6}^{\color{red}b} (x+ 2)^3 \; dx \leq 0 ∫−6b(x+2)3dx≤0